The answer of the above equation is 26.
Explaination:
Let the Christmas trees with stars be, Cs
& Christmas tree without star be, C
Christmas tree with 5 layers Ce & 6 layer be Cf
Let the wheels be, W
& Star be, S. divisions are mentioned according to alphabets,
Like wheel with 6 divisions as Wf & with 5 divisions We.
Now, rewriting the equations in C, W & S terms.
Equation (1); Ce + Ce + Ce = 21
Equation (2); Wf + Wf + Cs = 19
Equation (3); S + Wf + Cs = 15
Equation (4); Cf + 2S * We =?
So, initiating with equation (1),
Cs + Cs + Cs = 21
3Cs = 21
Cs = 7
Now substitute Cs value in equation (2),
Wf + Wf + Cs = 19
2 Wf + 7 = 19
2 Wf = 12
Wf = 6
So, wheel with 6 divisions, be 6 & so 1 division = 1
Now, solve equation (3).
S + Wf + Cs = 15
S + 6 + 7 = 15
Star, S = 2
So, we can calculate the value of the Christmas tree without stars easily,
Cs = C + S
C = 7 – 2
C = 5,
Similarly, if Christmas trees (5 layers) = 5
So, 1 layer = 1
So Christmas tree without star will be of 6 layers
& Final equation will be,
Cf + 2S * We =?
= 6 + (2 + 2) * 5
= 6 + 4 * 5
Cf + 2S * We = 6 + 20
Cf + 2S * We = 26
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