Count the triangles - Math Riddle
91.Math Riddles
How many triangles can you count in this shape?

- A.7
- B.8
- C.9
- D.10
Explanation : Count the triangle carefully without leaving any triangle inside
If you want to improve your mathematical skills and challenge your brain, these 100+ math riddles are for you. From basic arithmetic to advanced algebra, these math puzzles and math equations will test your problem solving abilities and help you hone your math skills. These riddles are a fun and engaging way to improve your math skills. Check your answers against the provided solutions or try to solve them all on your own. Either way, you'll be sure to have a good time while you're at it.
How many triangles can you count in this shape?
Explanation : Count the triangle carefully without leaving any triangle inside
Can you solve this number ?
Explanation : there are four intersecting points.
What should replace the question mark?
729
Explanation : 729, 27x27=729.
1=3, 2=3, 3=5, 4=4, 5=4, 6=3, 7=5, 8=5, 9=4, 10=3, 11=? 12=? Can you complete the sequence?
6
Explanation : 6. The numbers present represents the number of letters in the spelling of its corresponding number.
Two hens can lay two eggs in two minutes. If this is the maximum speed possible, what is the total number of hen needed to get 500 eggs in 500 minutes?
Explanation : Time is measured in minutes or seconds. Time is irreversible in nature as the prsent add to the future events. Given: Two hens can lay two eggs in two minutes. Find: The total number of hen needed to get eggs in minutes. Solution: According to the problem, eggs are layed in minutes by hens egg is layed in minutes by hens egg is layed in minute by egg is layed in minutes by Thus, egg is layed in minutes by hens Hence, hens are needed to get egg in minutes.
Peter was asked how old he was. His reply was like this; In a period of 2 years my age will be twice my age when you asked this five years ago. How old is he?
Explanation : Let Peter's age be X Years X+2=2(X 5) X+2=2X 10 X=12
100 coins fell down and got scattered inside a dark place. 90 of the coins fell with heads facing up and the rest 10 coins fell with tails up. You are asked to sort out these coins into 2 piles. However, each pile should have the same count of tails up coins. How is it possible?
Firstly, all the piles need not be of same size. I can make 2 piles, one with 90 coins and the other with 10 coins. Now just flip all the 10 coins on the pile. So the piles will have the same count of tails.
If 21 is added to four times a number, the result is 57.
Explanation : 4x + 21 = 57 4x = 36 x = 9
Can you solve the below equation? 30/6*2-3*2+12/2=?
Explanation : Follow BODMAS Rule So, 5*2 6 + 6 =10
Which number replaces the question mark? 30 6 2 3 2 12 2 ?
Explanation : As you can see the lower number rows are always bigger than upper row ones with the difference going up by 3 with every step 34 - 32 = 2 32 - 27 = 5 (difference going up by 3 from last difference) 56 - 48 = 8 (difference going up by 3 from last difference) ? - 19 = 11 (difference going up by 3 from last difference) So ? = 30
Can you solve the below quickfire equation?
Explanation : Ans : + 1 5x^2 = ?25 5x^2 = 5 X^2 = 5/5 X=?1 = + 1
Can you solve the below smiley equation?
Explanation : 180 30+30+30=90 10+30+10 =50 10+ 15+15=40 30+10*15= 180
Which three numbers have the same answer whether they are added or multiplied together
1,2,3
Explanation : 1,2,3 1+2+3 = 6 1*2*3 = 6
Can you solve the below viral equation?
Explanation : 24 8 + 8 / 2(1+3)= ? 8 + 8 / 2(4)= ? 8 + 4(4)= ? 8 + 16 = ? 24
2 2 = 00 3 3 = 03 4 4 = 08 5 5 = 15 6 6 = 24 7 7 = ??
35
Explanation : The value of RHS is (A*A) (A+A) i.e(2*2) (2+2) = 4 4 = 00 (3*3) (3+3) = 9 6 = 03 (4*4) (4+4) = 16 8 = 08 (5*5) (5+5) = 25 10 = 15 (6*6) (6+6) = 36 12 = 24 (7*7) (7+7) = 49 14 = 35