Math Challenge - There's A Three Digit Number Math Puzzle
Math puzzles are a fun and engaging way to test your problem-solving skills and logical reasoning abilities. Exercise your brain and make you think deeply. Try to solve the below math challenge and find the answer and explanation.
I am a three-digit number my second digit is four times bigger than the third digit my first digit 3 less than my second digit who am I?
Try to solve it. It's little tricky
Hint:You have to use an algebraic equation
Let the three numbers be 100s number a, 10s number b, and 1s number c.
therefore number will be 100a+10b+1c
Let the third number c be x
The alternate number is four times as big as the third number,
therefore 2nd number b = 4x
the first number is three lower than the alternate number, therefore 1st number a=(4x-3)
Now there are the following possibilities,
Since x is a number, it must lie between a single number of 1 and 9.
x cannot be 0 or further than 3 because If x is considered 0,
also the number a will be 0 and the resulting number will be only a two-digit number.
x cannot be 3 because
However, the alternate number b which is 4x, won't be between 1 and 9 if x = 3.
So, x can only take the value of c as 1 and 2.
However, 2nd number,
If x = 1 also the third number c will be 1.
b will be 4x = 4 and
the first number a will be 4x- 3 = 4- 3 = 1
Thus, the three-digit number will be 141.