100+ Challenging math riddles to keep your mind sharp

If you want to improve your mathematical skills and challenge your brain, these 100+ math riddles are for you. From basic arithmetic to advanced algebra, these math puzzles and math equations will test your problem solving abilities and help you hone your math skills. These riddles are a fun and engaging way to improve your math skills. Check your answers against the provided solutions or try to solve them all on your own. Either way, you'll be sure to have a good time while you're at it.

Magnifying Glass - Math Riddle

31. Math Riddles

Jim was examining an angle measuring 14 and 1/2 degrees, using his magnifying glass that magnifies everything two times. Under the glass, how large would that angle measure?

 

Answer: 14 and 1/2 degrees

Explanation :  

let's explain the magnification of the angle in a mathematical manner. We'll use the formula:

Magnified Angle = Original Angle × Magnification

In this case, the original angle is 14.5 degrees, and the magnification is 2 (since the magnifying glass makes everything look two times larger).

So, using the formula:

Magnified Angle = 14.5 degrees × 2 = 29 degrees

Therefore, the angle under the magnifying glass measures 29 degrees.

 

 

Laying Egg's -Math Riddle

32. Math Riddles

If a hen and a half lay an egg and a half in a day and a half, how many eggs will half a dozen hens lay in half a dozen days?

 

 

Answer: Two dozen (24) 

Explanation :  

Certainly! Let's break down the explanation in a mathematical manner.

The original statement says, "If a hen and a half lay an egg and a half in a day and a half, how many eggs will half a dozen hens lay in half a dozen days?"

We've already established that one hen lays one egg in one day. To represent this, we can use the following equation:

1 hen = 1 egg/day

Now, let's introduce the concept of time and the number of hens increasing four-fold:

Number of hens increased four-fold: 1.5 hens * 4 = 6 hens
Time available increased four-fold: 1.5 days * 4 = 6 days
With these increases, we want to find out how many eggs the 6 hens will lay in 6 days. To do this, we can set up a proportion based on the original information:

(1.5 hens / 1.5 days) = (6 hens / 6 days)

Now, to determine the number of eggs laid by the 6 hens in 6 days, we can calculate it as follows:

6 hens/day * 6 days = 36 eggs

So, when we increase both the number of hens and the amount of time available four-fold, the number of eggs increases 16 times:

16 * 1.5 (original rate) = 24 eggs

This equation illustrates how the number of eggs increases when both the number of hens and the time available are increased four-fold.

 

Added to the sum of their squares is 109 -Math Riddle

33. Math Riddles

There are two numbers whose product added to the sum of their squares is 109, and the difference of whose squares is 24. What are the two numbers?

 

 

Answer: 5 and 7. 

Explanation :  

We have two conditions:

The product of two numbers added to the sum of their squares is 109, which can be represented as:
xy + x² + y² = 109.

The difference of their squares is 24, which can be represented as:
x² - y² = 24.

Now, let's correctly solve these equations:

From Equation 2 (x² - y² = 24), you found that x² = 49, which implies x = 7. This part is correct.

However, the step where we substitute x = 7 into Equation 1 is where the error occurred:

(7)y + (7)² + y² = 109
7y + 49 + y² = 109

Now, let's correct the calculation:

7y + 49 + y² = 109

To isolate the terms involving y, subtract 49 from both sides:

7y + y² = 109 - 49

Now, it should be:

7y + y² = 60

Next, rearrange the terms:

y² + 7y = 60

To solve for y, let's rewrite the equation in the form of a quadratic equation:

y² + 7y - 60 = 0

Now, you can factor the quadratic equation:

(y + 12)(y - 5) = 0

Setting each factor equal to zero gives us two possible values for y:

y + 12 = 0, which leads to y = -12.
y - 5 = 0, which leads to y = 5.
So, there are two possible pairs of numbers that satisfy the given conditions:

x = 7 and y = -12
x = 7 and y = 5
Both pairs make the equations true, and the original problem has two valid solutions.

 

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Add five to twelve-Math Riddle

34. Math Riddles

I add five to twelve, and get five. Why is this correct?

 

Explanation :  

When it is 12 pm, adding five hours makes it 5 pm.

 

 

 

How many kids-Math riddle

35. Math Riddles

At a children's party, 
10 kids had juice, 
8 kids had cake, 
and 6 kids had juice and cake. 
How many kids were there at the party?

 

 

Answer: 12 kids

Explanation :  

We have the following information:

10 kids had juice (J).
8 kids had cake (C).
6 kids had both juice and cake (J ∩ C).
To find out how many kids were at the party in total, we can use set theory and the principle of inclusion-exclusion:

Total kids = (Kids with juice) + (Kids with cake) - (Kids with both juice and cake)

Total kids = 10 (J) + 8 (C) - 6 (J ∩ C)

Now, let's adjust the equation based on the information you provided:

Since 6 kids had both juice and cake, there are 8 - 6 = 2 kids who had cake (C) but not juice.

So, the adjusted equation becomes:

Total kids = 10 (J) + 2 (C, without J) - 6 (J ∩ C)

Now, plug in the values:

Total kids = 10 + 2 - 6
Total kids = 12

Therefore, there were 12 kids in total at the party. This method uses set theory and the principle of inclusion-exclusion to find the total number of kids, considering both the ones with juice and cake and those with only cake.

 

How many earrings are being worn in this club? - Math Riddle

36. Math Riddles

There is a certain club which is for men only. There are 600 men who belong to this club and 5% of these men wear one earring. Of the other 95% membership, half wear two earrings and the other half wear none. How many earrings are being worn in this club?

 

 

Answer: 600

Explanation :  

We have the following information:

5% of the men wear one earring.
The other 95% are divided into two groups: half wear two earrings, and half wear none.
Let's calculate it step by step:

First, we find out how many men wear one earring:

5% of 600 = (5/100) * 600 = 30 men.

Now, we know that 95% of the men belong to the other two groups (those who either wear two earrings or none). To find out the total number in this group, we calculate:

95% of 600 = (95/100) * 600 = 570 men.

As you correctly pointed out, half of the 95% (570) wear two earrings, and the other half wear none. Since they all belong to the same 95%, you can consider it as if they all wear one earring.

Now, to find the total number of earrings being worn in the club, we add the number of earrings worn by each group:

Total earrings = Earrings worn by men with one earring + Earrings worn by men with two earrings or none.

Total earrings = 30 (one earring) + 570 (effectively one earring) = 600 earrings.

 

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Bill was eight times the age of his son - Math Riddle

37. Math Riddles

Eight years ago, Bill was eight times the age of his son Bill Jr. Today, if you add their ages together, they add up to 52. How old are Bill and his son?

 

 

    Answer:Bill is 40, and Bill Jr. is 12.

    Explanation :  

    Eight years ago, Bill Jr. was x years therefore Bill was 8x

    Today

    (x+8) +(8x+8) = 52

    x+8 + 8x+8 = 52

    9x + 16 = 52

    9x = 52–16

    9x = 36

    Therefore x = 4

    Bill Jr. is

    x + 8 = 12

    4 + 8 = 12 years old

    Bill is

    8x + 8 = 32 + 8

    32 + 8 = 40 years old

    Therefore 12 + 40 = 52 years.

 

Three matches are sitting on a table - Math Riddle

38. Math Riddles

Three matches are sitting on a table. Without adding another make for three matches four. You are not allowed to break any of the matches. How can this be done?

 

Explanation :  

Shape the 3 matches into a roman numeral four.

 

 

Nonstop Train -Math riddle

39. Math Riddles

A nonstop train leaves Moscow for Leningrad at 60 mph. Another nonstop train leaves Leningrad for Moscow at 40 mph. How far apart are the trains 1 hour before they pass each other?

 

Answer:100 

Explanation :  

We have two trains:

  1. Train 1 is traveling at 60 mph.
  2. Train 2 is traveling at 40 mph.

One hour before they pass each other, they have been traveling towards each other for one hour. In that time, they will have covered a distance equal to their combined speeds.

So, the total distance covered by both trains together in one hour is:

Distance = Speed x Time

For Train 1: Distance covered by Train 1 = 60 mph x 1 hour = 60 miles

For Train 2: Distance covered by Train 2 = 40 mph x 1 hour = 40 miles

Combined distance covered by both trains = 60 miles (Train 1) + 40 miles (Train 2) = 100 miles.

Hence, one hour before they pass each other, the two trains are 100 miles apart. This illustrates how understanding the concepts of speed, time, and distance allows us to analyze and solve real-world scenarios involving moving objects.

 

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Three times as old as my sister was -Math Riddle

40. Math Riddles

One sister says of her younger sister: 
"Two years ago, I was three times as old as my sister was. In three years's time, I will be twice as old as my sister.? How old are they each now?

 

Explanation :  

One way to solve this math  is to use even numbers: The elder sister will be twice as old as her younger sister in three year's  time. This immediately rules out the elder sister currently being 8, 11, and 14, so she must be 17, and the younger sister 7.

 

 

Creature and Fill tank - Math Riddle

41. Math Riddles

There is a Creature which could double its size every day. So, if the Creature is put in a tank then it will fill the tank in 10 days. How many days would it take for the creature to fill 1/2 and 1/4 of the tank?

What is the next number - Math Riddle

42. Math Riddles

What is the next number in the series?

7,645 5,764 4,576 ?

 

 

   Answer: 6,457

   Explanation :  

   

Let's say you have a number represented as "ABCD," where A, B, C, and D are digits. In the given series:

  1. The last digit (D) is moved to the front.
  2. The other digits (A, B, and C) are shifted one place to the left.

So, mathematically, the transformation can be represented as:

Original Number: ABCD Transformed Number: DABC

In this way, the last digit is moved to the front to create the next number in the series. For example:

  1. For 7,645:

    • Last digit D = 5
    • The remaining digits ABC = 7,64
    • So, the transformed number is 5,7645.
  2. For 4,576:

    • Last digit D = 6
    • The remaining digits ABC = 4,57
    • So, the transformed number is 6,457.

You can use this mathematical pattern to generate the next number in the series by applying the same rule: moving the last digit to the front and shifting the other digits one place to the left.

 

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How many brothers and sisters are there in the family? - Math Riddle

43. Math Riddles

A boy has as many sisters as brothers, but each sister has only half as many sisters as brothers. 
How many brothers and sisters are there in the family?

A boy has as many sisters as brothers, but each sister has only half as many sisters as brothers. 
How many brothers and sisters are there in the family?

 

Explanation :  

Four brothers and three sisters.

 

Two whole Positive Number-Math riddle

44. Math Riddles

What two whole, positive numbers that have a one digit answer when multiplied and a two digit answer when added?

 

Explanation :  

 

Let the two whole, positive numbers be represented by and . The given conditions are:

  1. When multiplied, the result is a one-digit number: =Single Digit

  2. When added, the result is a two-digit number: =Two Digit Number

Now, let's consider the specific case of =1 and =9.

  1. Multiplication: 1×9=9

    The result is a single-digit number, which satisfies the first condition.

  2. Addition: 1+9=10

    The result is a two-digit number, fulfilling the second condition.

Thus, the numbers 1 and  9 meet both criteria. This demonstrates the mathematical solution to the given puzzle, where the multiplication of 1 and 9 yields a single-digit result, and the addition of 1 and 9 produces a two-digit sum.

 

Eight Eights - Math riddle

45. Math Riddles

Can you write down eight eights so that they add up to one thousand?

 

Explanation :  

Let's represent the arrangement using variables:

a=888 (Three eights)

b=88 (Two eights)

c=8+8+8 (Three individual eights)

Now, the given equation is:

Substituting the values of , , and :

888+88+8+8+8=1000

This shows the breakdown of the arrangement into its individual components. The combination of three eights, two eights, and three individual eights results in a sum of one thousand.

Thus, the mathematical explanation demonstrates how each part of the arrangement contributes to the total sum, fulfilling the condition 888+88+8+8+8=1000.

 

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