Answer: 5 and 7.
Explanation :
We have two conditions:
The product of two numbers added to the sum of their squares is 109, which can be represented as:
xy + x² + y² = 109.
The difference of their squares is 24, which can be represented as:
x² - y² = 24.
Now, let's correctly solve these equations:
From Equation 2 (x² - y² = 24), you found that x² = 49, which implies x = 7. This part is correct.
However, the step where we substitute x = 7 into Equation 1 is where the error occurred:
(7)y + (7)² + y² = 109
7y + 49 + y² = 109
Now, let's correct the calculation:
7y + 49 + y² = 109
To isolate the terms involving y, subtract 49 from both sides:
7y + y² = 109 - 49
Now, it should be:
7y + y² = 60
Next, rearrange the terms:
y² + 7y = 60
To solve for y, let's rewrite the equation in the form of a quadratic equation:
y² + 7y - 60 = 0
Now, you can factor the quadratic equation:
(y + 12)(y - 5) = 0
Setting each factor equal to zero gives us two possible values for y:
y + 12 = 0, which leads to y = -12.
y - 5 = 0, which leads to y = 5.
So, there are two possible pairs of numbers that satisfy the given conditions:
x = 7 and y = -12
x = 7 and y = 5
Both pairs make the equations true, and the original problem has two valid solutions.